X^2+40=184-10x

Solution for X^2+40=184-10x equation:

X^2+40=184-10X

We move all terms to the left:

X^2+40-(184-10X)=0

We add all the numbers together, and all the variables

X^2-(-10X+184)+40=0

We get rid of parentheses

X^2+10X-184+40=0

We add all the numbers together, and all the variables

X^2+10X-144=0

a = 1; b = 10; c = -144;
Δ = b2-4ac
Δ = 102-4·1·(-144)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*1}=\frac{-36}{2}
=-18
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*1}=\frac{16}{2}
=8
$